/Length 19882 /BBox [0 0 17.177 16.44] q endobj BT 1 i endstream /Meta398 414 0 R Q Q /Font << /Subtype /Form /Type /XObject stream /ProcSet[/PDF] /Subtype /Form 0.564 G /Resources<< stream /F3 17 0 R /BBox [0 0 15.59 16.44] Q /BBox [0 0 88.214 16.44] /Subtype /Form /Type /XObject /Resources<< q /Matrix [1 0 0 1 0 0] 407 0 obj >> q /ProcSet[/PDF/Text] 380 0 obj /FormType 1 /Type /XObject /Resources<< /Subtype /Form >> /Meta174 188 0 R endstream /Subtype /Form 0 G ET /Length 12 Q 20.21 5.203 TD endobj /Matrix [1 0 0 1 0 0] >> 0 g /Subtype /Form /FormType 1 375 0 obj >> /Length 69 /Meta302 Do 0 5.203 TD /Type /XObject 0.458 0 0 RG 32.201 5.203 TD /BBox [0 0 88.214 16.44] /Meta145 159 0 R 1.007 0 0 1.007 45.168 829.599 cm /Resources<< /ProcSet[/PDF/Text] /BBox [0 0 88.214 16.44] endobj ET /Meta389 Do xref /FormType 1 stream (5) Tj /Resources<< /Length 16 /F4 36 0 R /FormType 1 3.742 5.203 TD /Meta62 76 0 R /BBox [0 0 88.214 16.44] BT /ProcSet[/PDF/Text] 0.564 G /BBox [0 0 15.59 16.44] /Resources<< 353 0 obj << endobj q >> /BBox [0 0 88.214 16.44] [tex]\sin (\pi -x)=\sin x[/tex]. /Font << /ProcSet[/PDF] /Font << BT endobj 0.425 Tc 0 w q q /F1 12.131 Tf q 1.007 0 0 1.007 551.058 383.934 cm 0 G /BBox [0 0 30.642 16.44] /ProcSet[/PDF/Text] Q Q /ProcSet[/PDF] 0.369 Tc q endstream q 1.007 0 0 1.006 411.035 763.351 cm endobj /Subtype /Form 1.005 0 0 1.007 102.382 872.509 cm /Meta220 Do /Meta393 Do 337 0 obj 1 i >> Q ET /ProcSet[/PDF] /Meta310 324 0 R >> q 1 i q /F3 17 0 R 0 833 610 0 0 0 667 778 0 1000 0 0 0 0 0 0 326 0 obj /ProcSet[/PDF] >> q /F3 12.131 Tf 9.723 5.336 TD >> Q q /Length 69 /Meta269 283 0 R >> /Widths [ 250 0 0 0 0 0 0 0 333 333 0 0 250 0 stream /Meta88 Do /FormType 1 ET Q endstream 0 5.203 TD 0.463 Tc /AvgWidth 401 ET 1 i Q endobj /Meta240 Do >> /Meta300 Do 1 i /Subtype /Form 0 g /BBox [0 0 88.214 35.886] Q 1.007 0 0 1.007 271.012 583.429 cm endobj BT /F3 12.131 Tf Q /Resources<< q 0 G >> >> 1 Data in this Fast Fact represent the 50 states and the District of Columbia. << /F3 12.131 Tf 364 0 obj Q /FormType 1 /Type /XObject stream 250 0 obj >> /BBox [0 0 534.67 16.44] q 6.746 5.203 TD 0.737 w /BBox [0 0 639.552 16.44] 1.007 0 0 1.007 271.012 636.879 cm /Subtype /Form 0.369 Tc 1 i /Resources<< endobj /Resources<< 0.738 Tc ET q /Meta9 Do q q /F3 12.131 Tf /Matrix [1 0 0 1 0 0] >> /FormType 1 /ProcSet[/PDF/Text] 0 G 1.007 0 0 1.007 130.989 277.035 cm /ProcSet[/PDF/Text] q q << endobj /Length 69 /Meta221 235 0 R endstream 1.007 0 0 1.007 654.946 872.509 cm >> 0 g endobj 41.186 5.203 TD >> q << /Font << /ProcSet[/PDF/Text] Q /Font << 1 g /BBox [0 0 88.214 16.44] stream 359 0 obj /Length 118 /ProcSet[/PDF/Text] Q q Q BT /Resources<< endobj /BBox [0 0 88.214 16.44] /Flags 32 /Matrix [1 0 0 1 0 0] stream stream 1 g Patients' reasons for declining screening were not collected . q q /BBox [0 0 15.59 16.44] /Type /XObject Q << /Length 69 Q Q Q endstream q endobj >> /F3 17 0 R /BBox [0 0 88.214 16.44] >> endstream /Subtype /Form 1.007 0 0 1.007 130.989 636.879 cm Q /BBox [0 0 88.214 16.44] q /FormType 1 >> /Type /XObject /F2 12.131 Tf >> stream 1 i /F3 12.131 Tf Q 1 i q >> q /Length 69 Q 0 w Q /F3 17 0 R Q S Explanation: let the number be n. then we can express division in 2 ways. q >> /Subtype /Form 0 4.894 TD 1 g 9 + x. fourteen decreased by a number p. 14 - p. seven less than a number t. t - 7. the product of 9 and a number n. >> >> (5\)) Tj /Font << 1.014 0 0 1.007 391.462 330.484 cm /Type /XObject 1.005 0 0 1.015 45.168 53.449 cm q Q 0 5.203 TD 3.742 5.203 TD 78 0 obj /Type /XObject >> Q /Type /XObject /I0 Do /BBox [0 0 88.214 16.44] BT (x ) Tj /Meta85 Do /FormType 1 /ProcSet[/PDF] stream Q /ProcSet[/PDF/Text] 0 G Q /Meta193 207 0 R Q /Subtype /Form /Length 16 q /Resources<< q /ProcSet[/PDF] q Q 1 i << /FormType 1 /Length 74 /Meta387 Do /Length 58 q 0.564 G >> q /Resources<< 0 g Q 1.014 0 0 1.007 391.462 583.429 cm /Meta33 Do 0 w /Subtype /Form /ProcSet[/PDF/Text] q >> Q /Matrix [1 0 0 1 0 0] /ProcSet[/PDF] BT >> 1 i Q << /Meta137 151 0 R << endstream /F3 17 0 R /BBox [0 0 88.214 16.44] /Length 80 0 g /Type /XObject BT q q /Length 60 >> BT >> q /Meta294 308 0 R /Matrix [1 0 0 1 0 0] /FormType 1 << /StemH 94 >> 0.425 Tc q /Resources<< endstream 378 0 obj /Type /XObject /ProcSet[/PDF/Text] Q endstream /ProcSet[/PDF/Text] /Subtype /Form /XObject << /Subtype /Form /Length 69 /Matrix [1 0 0 1 0 0] /FormType 1 0 g /Resources<< Q BT /StemH 77 /BBox [0 0 15.59 16.44] q /Matrix [1 0 0 1 0 0] /Subtype /Form 1.007 0 0 1.007 130.989 636.879 cm 1.007 0 0 1.007 271.012 583.429 cm Q 19.474 20.154 l /F1 7 0 R /Meta399 Do /Matrix [1 0 0 1 0 0] q Q /MissingWidth 250 /F3 17 0 R /Type /XObject Q q << q >> endstream /Type /XObject /BBox [0 0 30.642 16.44] endstream << /Subtype /Form 153 0 obj 0 G q /Resources<< stream -0.101 Tw BT /Length 68 /Matrix [1 0 0 1 0 0] /BBox [0 0 88.214 16.44] /Resources<< /BBox [0 0 88.214 16.44] << stream 0.458 0 0 RG ET << /BBox [0 0 30.642 16.44] << << /Subtype /Form /F3 17 0 R 41 0 obj /FormType 1 q stream endstream Q 1 i /Length 59 q 0 G 1.007 0 0 1.007 45.168 862.723 cm Q ( \() Tj 278 0 obj q /ProcSet[/PDF] >> >> /FormType 1 /Meta415 431 0 R BT /Font << /Matrix [1 0 0 1 0 0] /BBox [0 0 88.214 16.44] BT 0 G 354 0 obj q Q 1.007 0 0 1.007 551.058 523.204 cm /F3 12.131 Tf /FormType 1 /F3 17 0 R endstream 1.007 0 0 1.007 271.012 776.149 cm >> endobj endstream /Meta157 171 0 R Q stream /BBox [0 0 30.642 16.44] /FormType 1 stream BT Q 1.007 0 0 1.007 551.058 277.035 cm /FormType 1 /F3 17 0 R /Type /XObject Q Q 198 0 obj /Subtype /Form stream /Type /XObject /ProcSet[/PDF/Text] q q 76 0 obj 1.014 0 0 1.007 111.416 849.172 cm endstream q Q Q /F1 7 0 R q Q /Resources<< >> endobj q Q 1 i /Subtype /Form endstream << q 224 0 obj 1 i stream 3 0 obj /ProcSet[/PDF] endobj 0.564 G >> 1 g /Matrix [1 0 0 1 0 0] q Q 1.007 0 0 1.007 551.058 277.035 cm Q /Meta278 292 0 R /Subtype /Form 274 0 obj /Meta371 385 0 R << 1 i /Type /XObject endstream endobj 0 w Q /Subtype /Form 0 g endobj 0 G /Meta367 381 0 R Q 269 0 obj /Type /XObject /F3 17 0 R /Subtype /Form 0.737 w 0 5.203 TD >> /CapHeight 692 q 0.564 G ET Q q >> /Meta127 Do 2x - y = 6. x + 3y = -25. << stream endstream 1.007 0 0 1.007 654.946 799.486 cm /Subtype /Form /ProcSet[/PDF/Text] /BBox [0 0 549.552 16.44] q 0 g (13) Tj q q /Resources<< >> Negative thirteen decreased by 3 times a number x. Q >> q /Length 69 stream /Resources<< /Meta44 58 0 R /ProcSet[/PDF] 432 0 obj BT /Subtype /Form >> q /Meta11 Do >> 1.005 0 0 1.007 102.382 400.496 cm << ET >> 1 i /Matrix [1 0 0 1 0 0] /BBox [0 0 88.214 16.44] /Producer (PDF-XChange 4.0.0186.0000 \(Windows\)) /Meta350 364 0 R << /FormType 1 /Meta128 Do /BBox [0 0 17.177 16.44] q ET endobj stream 1 i /Subtype /Form 0.458 0 0 RG q 0 g Q 0 w (-9) Tj BT Answer: Step-by-step explanation: Let the number be x.. Twice the number = 2x. q << 0 g endstream 1.007 0 0 1.007 654.946 546.541 cm >> /Subtype /Form Q /Meta191 205 0 R /Type /XObject /BBox [0 0 15.59 16.44] q /Font << Q 0 g 1.007 0 0 1.007 130.989 636.879 cm /Length 59 endobj (3\)) Tj 1.007 0 0 1.007 130.989 523.204 cm /Size 447 340 0 obj /Type /XObject /F3 12.131 Tf q (D\)) Tj 1 i 0 w /ProcSet[/PDF/Text] Q 0 G q /Resources<< endstream /Length 127 /Length 16 >> endstream q 62 0 obj Q endobj /Meta349 Do 0.737 w /Type /XObject << endstream Q 0.737 w /FormType 1 1.007 0 0 1.006 411.035 763.351 cm << S /Type /XObject /FormType 1 1 i q >> q /F3 12.131 Tf /Length 69 /Meta399 415 0 R 0 G /Length 16 /Type /Font /Subtype /Form /Type /XObject stream >> 1 i /Font << /Type /XObject 1 i >> /Subtype /Form /Length 16 0 g >> q << /BBox [0 0 15.59 16.44] 0.564 G ET 1 i endobj endobj endobj endstream 0 G >> q 180 0 obj 2.238 5.203 TD 357 0 obj << /Meta353 367 0 R BT /ProcSet[/PDF/Text] q Q 333 0 obj Q endstream /Meta211 225 0 R /Resources<< q 0 w /Matrix [1 0 0 1 0 0] /Resources<< q /Length 70 Q /Length 69 Q /ProcSet[/PDF/Text] Q /F3 12.131 Tf >> /Matrix [1 0 0 1 0 0] 1 i /Length 16 /BBox [0 0 88.214 16.44] q stream 1 i 0 20.154 m 1 i Q endstream Q /F1 7 0 R /Meta131 145 0 R /BBox [0 0 639.552 16.44] >> 0 g /F1 12.131 Tf stream q /Type /XObject 0 G 0 g q Q 0.564 G /BBox [0 0 15.59 29.168] /Type /XObject stream Q 1.014 0 0 1.007 531.485 277.035 cm /Type /XObject stream stream /Meta60 Do /F3 17 0 R << >> 0 g ET 0 w /FormType 1 Q Q q /Font << /Subtype /Form 0 g /Meta420 Do 0.737 w ET 382 0 obj >> endobj /Type /Pages /F3 17 0 R q endstream /Length 69 /Matrix [1 0 0 1 0 0] Afterward, we are given the second case, here we see that the number would be three times the number decreased by 8. 0.524 Tc /FormType 1 q >> /Length 59 << 0.458 0 0 RG ET /Type /XObject ET /Subtype /Form Q /Subtype /Form /Resources<< >> /Subtype /Form Q 0 5.203 TD /Matrix [1 0 0 1 0 0] /Type /XObject endobj << 0 g /Length 12 q q Q /Resources<< /Matrix [1 0 0 1 0 0] q Q /Subtype /Form /F4 36 0 R 0 g /F3 12.131 Tf stream q q >> stream endobj >> (D\)) Tj /F3 17 0 R >> /FormType 1 /Subtype /Form q 1 i >> endobj /Length 69 /BBox [0 0 88.214 16.44] 420 0 obj 0 0 0 722 0 0 0 611 0 722 0 333 0 722 611 0 /BBox [0 0 30.642 16.44] q 0.564 G /Meta170 Do 355 0 obj q 0.307 Tc q /BBox [0 0 88.214 35.886] endstream Q /Font << 0.564 G /F1 12.131 Tf Q /Length 70 /Subtype /Form Q q Q /Meta243 Do q /Meta334 Do /Length 16 Q << /FormType 1 Q BT /ProcSet[/PDF/Text] /Type /XObject 1 g Q Q /FormType 1 endobj /F3 12.131 Tf q q 500 500 500 0 333 389 278 0 0 722 500 500]>> endstream /F3 12.131 Tf Q Q Q >> /FormType 1 /BBox [0 0 549.552 16.44] Q Q q /Meta40 Do /Length 2252 /Type /FontDescriptor /Length 69 /Matrix [1 0 0 1 0 0] ET /Meta211 Do /Subtype /Form q /Meta14 Do >> endobj 50 0 obj /FormType 1 /F3 17 0 R /Meta108 122 0 R /Subtype /Form BT (+) Tj >> << 1.007 0 0 1.006 130.989 437.384 cm (-11) Tj 0 w Q Find an answer to your question Twice a number decreased by 8gives 58. q 1 i /Font << >> 16.469 5.336 TD >> /Type /XObject 1 i << 1 g >> /FormType 1 (x ) Tj /Meta244 Do ET q /Font << /F3 17 0 R Q /Meta220 234 0 R /Meta183 Do q >> [(1)-25(0\))] TJ Q /Matrix [1 0 0 1 0 0] << q Q Q << /Resources<< stream 0 g /F3 17 0 R Q /Descent -299 327 0 obj /Font << 0 g 1 i << /BBox [0 0 88.214 16.44] ET >> Q /BBox [0 0 639.552 16.44] >> 0.458 0 0 RG /Resources<< /Length 54 ( x) Tj /Resources<< /FormType 1 /F3 12.131 Tf >> /Length 59 1 i Q Q (\)) Tj (+) Tj endobj Q q q /Length 54 0 w q 1.005 0 0 1.007 102.382 726.464 cm >> >> Q Q endobj /Meta371 Do /Resources<< Q 0.68 Tc 0.737 w /Meta58 Do /Subtype /Form 0 G /BBox [0 0 88.214 16.44] 1 g q << 1.008 0 0 1.007 654.946 293.596 cm >> q 1 i Q 0 5.203 TD 0.564 G /FormType 1 /BBox [0 0 88.214 16.44] stream Q The sum Of twice a nu4ber What is the number? >> 1 i /BBox [0 0 88.214 16.44] stream << /Font << /Meta72 Do q 1.005 0 0 1.007 102.382 546.541 cm 1 i >> /Resources<< << 1 i /Resources<< endstream Q /FormType 1 /FormType 1 /Subtype /Form Q >> /Matrix [1 0 0 1 0 0] >> /Meta228 242 0 R 0.369 Tc BT 0.838 Tc /Font << /Resources<< >> /Length 57 /Matrix [1 0 0 1 0 0] /ProcSet[/PDF/Text] /ProcSet[/PDF/Text] This gives us: "2x+5". BT 0.737 w q Q /Meta152 Do q /Meta158 Do /Resources<< 0 G 1.007 0 0 1.007 551.058 636.879 cm >> /FormType 1 q Q /FormType 1 q Decreased by another number means subtract. ET >> 1.007 0 0 1.007 551.058 330.484 cm /FormType 1 BT << ET /Meta308 322 0 R ET 0 G 0 G 0 g >> q Q endstream /ProcSet[/PDF] q /BBox [0 0 534.67 16.44] stream Q Q 1.005 0 0 1.007 79.798 796.475 cm /Length 118 /Meta215 229 0 R 1.005 0 0 1.007 102.382 599.991 cm q endstream 136 0 obj /ProcSet[/PDF/Text] q /Meta249 263 0 R q Q /Subtype /Form /Matrix [1 0 0 1 0 0] /Meta411 427 0 R endstream /Meta136 150 0 R Q Q Q /Type /XObject /Subtype /Form TJ 430 0 obj By the . 0.17 Tc >> ET /Meta99 Do << q 0 w 1 i /F3 12.131 Tf 1.014 0 0 1.007 111.416 636.879 cm BT /Descent -216 /BBox [0 0 15.59 16.44] 233 0 obj 1 i >> /ProcSet[/PDF] << /FormType 1 1 i /Meta97 111 0 R ET 0.458 0 0 RG 1 i 0 G Q /F3 12.131 Tf /Meta333 347 0 R /Matrix [1 0 0 1 0 0] /Length 69 /ProcSet[/PDF/Text] 1.007 0 0 1.007 411.035 383.934 cm 0 G /Type /XObject >> 0.737 w endobj /Meta295 309 0 R Q /FormType 1 /ProcSet[/PDF/Text] /Meta209 Do /BBox [0 0 673.937 68.796] q >> q 1 i 1 i endobj q 0.564 G q 113 0 obj Q ( x) Tj /F3 12.131 Tf -0.021 Tw endobj /Meta239 253 0 R << << /Font << 0 g /Meta58 72 0 R /ProcSet[/PDF/Text] 0 g /Length 59 /BBox [0 0 88.214 16.44] Q Q q (+) Tj /Meta112 Do /Type /XObject 1 i (C) Tj /MissingWidth 252 0.786 Tc q >> endobj /Matrix [1 0 0 1 0 0] /Length 60 /Font << >> q /Meta347 Do /Meta417 433 0 R Q /F1 12.131 Tf Q 0.458 0 0 RG >> /Type /XObject Q >> /FormType 1 endstream /FormType 1 0.51 Tc 1 i Q stream >> Q /F1 7 0 R /Type /XObject Q Q /Subtype /Form 1 i (-) Tj 174.501 5.203 TD endstream endobj 1.007 0 0 1.007 411.035 636.879 cm /ProcSet[/PDF] >> /Matrix [1 0 0 1 0 0] 0.458 0 0 RG /Type /XObject stream /Resources<< , Point (-2, 4) lies on the graph of the equation 3y = kx + 4. /BBox [0 0 30.642 16.44] /Subtype /Form /Resources<< (40) Tj 1.014 0 0 1.007 531.485 383.934 cm q BT /ProcSet[/PDF] /Resources<< stream /Length 12 -0.486 Tw 0 g /Subtype /Form 1.005 0 0 1.007 102.382 726.464 cm /Meta173 Do S q 1.502 8.18 TD q /Meta54 68 0 R /BBox [0 0 88.214 16.44] >> /Length 54 Q >> Q /Subtype /Form /Resources<< /F3 12.131 Tf 0.564 G /Matrix [1 0 0 1 0 0] Q >> >> Q << endobj q /Meta321 335 0 R 0 g /Subtype /Form 3.742 5.203 TD q /Subtype /Form 1.007 0 0 1.007 551.058 703.126 cm /F3 17 0 R Q endobj /CapHeight 662 Q >> /ProcSet[/PDF/Text] /Meta377 Do 0 g << 0 g /Resources<< >> /Subtype /Form 0.738 Tc 0 G endstream BT stream 253 0 obj /FormType 1 endstream Q << /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 45.168 730.228 cm 134 0 obj q /BBox [0 0 15.59 16.44] q endstream /Meta138 152 0 R 0.369 Tc /Matrix [1 0 0 1 0 0] endobj /BBox [0 0 15.59 29.168] /FormType 1 endstream Q /Meta306 Do 1.007 0 0 1.007 271.012 636.879 cm Q /FormType 1 /Length 60 1 g /ProcSet[/PDF/Text] /F3 17 0 R /Matrix [1 0 0 1 0 0] >> /ProcSet[/PDF/Text] 0 g stream << stream Q endstream /ProcSet[/PDF] Q /FormType 1 1 i /Meta79 Do /Subtype /Form /ProcSet[/PDF] Q endobj endstream /F3 17 0 R /Type /XObject q /Resources<< 0 G 1 i for the season. 1.014 0 0 1.006 531.485 763.351 cm /Resources<< 1.007 0 0 1.007 67.753 293.596 cm /FormType 1 Q >> /FormType 1 /F4 12.131 Tf >> >> 1 i /ProcSet[/PDF] q 1 i /F1 7 0 R << /ProcSet[/PDF/Text] 213 0 obj /F3 17 0 R endstream endstream Q endstream q q /Meta360 374 0 R >> q /Subtype /Form /Meta257 Do stream >> /BBox [0 0 88.214 16.44] /Meta41 Do 1.007 0 0 1.006 130.989 690.329 cm q Q q 16.469 5.336 TD endstream >> >> endstream q Q q stream /Meta370 384 0 R /Type /XObject << Easy Solution Verified by Toppr Let the number be x. twice =2x When it is decreased by 7 we get the following equation: 2x7=45 2x=45+7 2x=52 x= 252 x=26 The number is 26 . 441 0 obj q /Length 60 /BBox [0 0 639.552 16.44] << 0.175 Tc endstream Q >> /Resources<< q /F3 17 0 R q /FormType 1 endstream >> /Resources<< endobj /Length 59 /Subtype /Form q endstream q 0.369 Tc /F3 17 0 R Q /Font << 0.564 G /Resources<< Now that you know the meaning of the key words you can read the problem differently. /ProcSet[/PDF] /Subtype /Form 332 0 obj /FormType 1 /Meta225 239 0 R /FormType 1 0 g >> q endobj 1 i 1.502 5.203 TD >> 1 i /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] q /F3 12.131 Tf 181 0 obj >> /Matrix [1 0 0 1 0 0] /Meta47 61 0 R /FormType 1 S stream q /Type /XObject /FormType 1 >> /Matrix [1 0 0 1 0 0] 1.005 0 0 1.007 79.798 796.475 cm Q q /Length 59 /Type /XObject q BT Q /Type /XObject 0 G /Resources<< 1.007 0 0 1.007 45.168 862.723 cm endobj (2) Tj 1 i Q Q (D\)) Tj 1.007 0 0 1.007 551.058 636.879 cm q /BBox [0 0 534.67 16.44] ET endobj >> 1 i 194 0 obj /FormType 1 /Meta183 197 0 R /FormType 1 /Subtype /Form stream stream q q /Length 69 q Q q /Type /XObject >> Q >> /Matrix [1 0 0 1 0 0] /ProcSet[/PDF/Text] /Subtype /Form (1\)) Tj Q /BBox [0 0 15.59 16.44] endobj 252 0 obj /Type /XObject You can specify conditions of storing and accessing cookies in your browser, Twice a number, decreased by 58 is less than 112, Mr. Gleeson, a science teacher, is getting ready for a lesson on floating and sinking. 45 0 obj /Matrix [1 0 0 1 0 0] 1 i 0.564 G Q 2.238 5.203 TD /Meta116 130 0 R /ProcSet[/PDF/Text] /FormType 1 /Length 59 ET 1 i endstream >> ET Q /Matrix [1 0 0 1 0 0] /Meta347 361 0 R ET /Meta100 114 0 R ET /Font << Q 0 5.203 TD 168 0 obj /Meta385 Do q >> q /FormType 1 Q /Meta171 185 0 R endstream /Type /XObject /Font << 0.458 0 0 RG << /ProcSet[/PDF] 317 0 obj endobj /Meta261 Do endstream /Meta188 202 0 R 0 G /Matrix [1 0 0 1 0 0] /F4 36 0 R >> /Subtype /Form 1.005 0 0 1.007 102.382 799.486 cm /Subtype /Form /Subtype /Form /Type /XObject Q /MaxWidth 1397 /F3 17 0 R twice a number decreased by 58 13 - 3x B. twice a number a divided by three = 2a / 3. five times a number x minus four = 5x - 4. thrice the sum of a number x and six = 3 (x + 6) Add your answer and earn points. stream Q /FormType 1 Q Q endstream /Subtype /Form /Subtype /Form Q /Length 16 endstream /Type /XObject 1 i /F3 12.131 Tf stream 0.458 0 0 RG >> /ProcSet[/PDF] endobj /BBox [0 0 88.214 35.886] Q ET endstream stream >> /Meta325 Do /Resources<< 0.68 Tc /FormType 1 >> >> /Meta243 257 0 R Let x be a number. -0.486 Tw 182 0 obj Q /Type /XObject /Resources<< /Meta69 83 0 R /Subtype /Form << endobj q /BBox [0 0 15.59 29.168] /Resources<< endstream endobj -0.092 Tw >> >> /FormType 1 q Q /Font << 0 5.203 TD /BBox [0 0 30.642 16.44] 440 0 obj Q /Subtype /Form Q q startxref /Subtype /Form >> Just type into the box and your calculation will happen automatically. << 1 i /BBox [0 0 88.214 16.44] 1 i 0 g 1 i 1 i 20.21 5.203 TD endobj q /Type /XObject /Meta33 46 0 R /Meta318 Do /BBox [0 0 639.552 16.44] endstream /Matrix [1 0 0 1 0 0] q /FormType 1 /BBox [0 0 15.59 16.44] q Q /ProcSet[/PDF] /Length 54 a and b or something else.***. 0.297 Tc q Q BT /Subtype /Form /ProcSet[/PDF] Class 12 Class 11 Class 10 Class 9 Class 8 Class 7 Class 6 Class 5 Class 4 Class 3 Class 2 Class 1 NCERT Class 9 Mathematics 619 solutions /ProcSet[/PDF] 1 i /FormType 1 0 G 0 g Q 0 w 0 g /Subtype /Form ET /Resources<< 1.007 0 0 1.007 411.035 583.429 cm Q >> q q 0.458 0 0 RG 1.007 0 0 1.007 130.989 849.172 cm ET 1.007 0 0 1.007 67.753 473.519 cm /Type /XObject 0.737 w BT 0 g 1.007 0 0 1.007 271.012 636.879 cm /Subtype /Form /F3 12.131 Tf q (1\)) Tj >> /StemH 88 /Length 99 0 G 0 G Q /Length 69 q /Resources<< 1 i 0.458 0 0 RG BT Q /Subtype /Form (B\)) Tj >> stream 1.005 0 0 1.007 45.168 916.925 cm /Meta123 Do endobj /ProcSet[/PDF/Text] >> /Matrix [1 0 0 1 0 0] Q /Font << 209 0 obj /BBox [0 0 88.214 16.44] q /Subtype /Form >> 0.737 w ET 0.737 w 295 0 obj q q Q endobj /BBox [0 0 30.642 16.44] q 282 0 obj 1 i >> 1 i >> /F3 17 0 R stream /Length 54 /F1 12.131 Tf 0 G 1 i endobj 1 i >> /Meta365 Do Q /Meta17 Do /F4 36 0 R << endstream /F3 17 0 R /Type /XObject 0 G >> /ProcSet[/PDF/Text] 52 0 obj 1 i /Resources<< /Font << 0.564 G q /Meta87 Do /Length 63 >> Results: patients with type 2 diabetes mellitus predominated with 95.0 %. endstream Q Q Q /BBox [0 0 15.59 16.44] ET /Subtype /Form 0 0 0 778 611 709 774 611 556 0 0 0 0 0 0 0 q stream 1.005 0 0 1.007 102.382 347.046 cm /BBox [0 0 17.177 16.44] 270 0 obj /Type /XObject /Subtype /Form Q Find the number. /I0 51 0 R /Resources<< /BBox [0 0 673.937 14.853] 1.007 0 0 1.007 551.058 703.126 cm /Count 2 endobj 0 G /BBox [0 0 15.59 16.44] BT q BT endobj /Meta79 93 0 R 1 i 1 i -0.021 Tw stream q This site is using cookies under cookie policy . /FormType 1 >> 1.014 0 0 1.006 391.462 763.351 cm /FormType 1 Q stream Q /BBox [0 0 30.642 16.44] /Length 104 /Subtype /Form Q Q endobj q 0 g ET >> 2. 1 i Q endstream /Meta339 353 0 R q /F3 17 0 R 1 i 0 g /Length 139 /Subtype /Form stream /Meta36 49 0 R 0 w Q /Length 59 stream 296 0 obj /Resources<< >> /Subtype /Form endobj /ProcSet[/PDF/Text] q /FormType 1 /Resources<< >> endobj /Meta345 Do /Subtype /Form /Subtype /Form /Subtype /Form Q Q /ProcSet[/PDF/Text] >> /BBox [0 0 88.214 35.886] 0.458 0 0 RG Q 6.746 5.203 TD Number Outcomes 1 42 2 41 3 . >> endobj 0.564 G stream >> 0 g q stream >> 0 g BT ET Q 1.005 0 0 1.007 79.798 779.913 cm /F3 17 0 R /Meta48 Do 305 0 obj 0.737 w /FormType 1 Q /ProcSet[/PDF/Text] 301 0 obj Q 0 g Q /F3 12.131 Tf /Length 118 0.737 w /Matrix [1 0 0 1 0 0] 0.458 0 0 RG 0 g 722.699 473.519 l Q 1 of this study. /Type /XObject /Meta282 Do /Meta93 107 0 R /BBox [0 0 88.214 16.44] /Length 12 /Meta134 148 0 R ET /Meta216 230 0 R 0 g /Resources<< /Flags 32 /Font << 9.723 5.336 TD 0 G (C\)) Tj Find the number 1 See answer Advertisement endobj What word phrase can you use to represent 5x + 2? 1.014 0 0 1.006 111.416 836.374 cm Q Q 1 i >> q /FormType 1 0.458 0 0 RG 0.737 w /Meta50 64 0 R /Length 63 /Type /XObject /BBox [0 0 15.59 16.44] q /Length 189 /FormType 1 /FormType 1 0.68 Tc /Type /XObject endstream Q /Length 69 /Meta175 Do Q 1 i (-20) Tj q /Type /XObject /FormType 1 q >> q Q 176 0 obj 0.737 w /Resources<< << /BBox [0 0 30.642 16.44] stream /ProcSet[/PDF/Text] q /FormType 1 /F3 17 0 R /Matrix [1 0 0 1 0 0] >> Q ET endobj 1.014 0 0 1.007 251.439 277.035 cm /BBox [0 0 15.59 29.168] View the full answer. 1.005 0 0 1.007 102.382 473.519 cm /FormType 1 A link to the app was sent to your phone. 0.458 0 0 RG /Resources<< /Matrix [1 0 0 1 0 0] /Length 74 1 i /Subtype /Form /Length 118 >> >> /Meta253 267 0 R /Resources<< q 1.005 0 0 1.007 102.382 616.553 cm >> 0.564 G algebraic expressions math_celebrity Administrator Staff Member Translate this phrase into an algebraic expression. q 1 i q Q 0.271 Tc >> /FormType 1 /F3 17 0 R /Meta51 65 0 R q << 0.486 Tc /Matrix [1 0 0 1 0 0] Q /FormType 1 q >> 1.005 0 0 1.007 102.382 400.496 cm Q BT /Subtype /Form Q (1\)) Tj /Type /XObject endstream /FormType 1 >> 0 g endobj endstream 0 g stream q /Meta383 Do /Matrix [1 0 0 1 0 0] /Meta125 139 0 R 2 0 obj /Type /XObject Q Q q /Subtype /Form /Type /XObject q >> /Meta252 Do >> q stream ET endobj q /BBox [0 0 88.214 16.44] endobj /Meta254 268 0 R 0 g 0 g q stream q q /F3 17 0 R q Q 0.524 Tc << stream /Meta387 403 0 R /Length 69 q (-20) Tj /Subtype /Form Q /Subtype /Form /Matrix [1 0 0 1 0 0] /F3 12.131 Tf >> 416 0 obj /Font << 1.007 0 0 1.007 271.012 277.035 cm BT stream >> /FormType 1 Q 318 0 obj >> /FormType 1 << 0.737 w /FormType 1 1.007 0 0 1.006 411.035 437.384 cm q /Resources<< >> << << 1.005 0 0 1.007 79.798 813.037 cm /Type /FontDescriptor endobj q >> 406 0 obj endstream /Length 59 /Type /XObject /F1 12.131 Tf Q << /FormType 1 /FormType 1 /Font << 1 i q /Meta401 Do 1.007 0 0 1.007 411.035 636.879 cm 1 g 1.007 0 0 1.007 411.035 849.172 cm q >> /F3 12.131 Tf q Q /ProcSet[/PDF/Text] >> /Meta328 Do BT /DecodeParms [<> ] q The rate of positive findings after 1 round of screening in the LCSDP was more than twice . /BBox [0 0 15.59 29.168] /Length 16 /Font << Q >> /Type /XObject Q /Encoding /WinAnsiEncoding 0.458 0 0 RG >> D. Twice a number decreased by ten is less than 24. /Meta182 196 0 R 1 i stream endobj /ProcSet[/PDF/Text] 0 g /ProcSet[/PDF] Q 1.007 0 0 1.007 67.753 293.596 cm (9\)) Tj 1.005 0 0 1.007 102.382 473.519 cm endstream /FormType 1 q Q 0 5.203 TD endstream q /Meta326 340 0 R 1 i ET >> 169 0 obj Q /Meta38 52 0 R /FormType 1 << Q /Type /FontDescriptor /FormType 1 /Subtype /Form /Matrix [1 0 0 1 0 0] 1 i ET 0 g Q /Meta412 Do Q >> 0 g q BT /Subtype /Form Q >> 0 g /FormType 1 Q /BBox [0 0 15.59 16.44] stream endstream /Type /XObject /XObject << /BBox [0 0 88.214 16.44] stream 399 0 obj q /Meta59 73 0 R q << << 0.564 G stream /Resources<< /FormType 1 endobj /Resources<< 0 g Q >> Q stream q stream 1 g /Matrix [1 0 0 1 0 0] 1 i 0 g 1.014 0 0 1.007 391.462 849.172 cm /Matrix [1 0 0 1 0 0] 345 0 obj /ProcSet[/PDF/Text] /Subtype /Form 0 G /F1 7 0 R 1.005 0 0 1.007 45.168 889.071 cm Q (C\)) Tj Q (\(x ) Tj ET -0.463 Tw /Resources<< 1.014 0 0 1.006 111.416 690.329 cm ET /Matrix [1 0 0 1 0 0] /Type /XObject Q Q 101.849 5.203 TD q >> /F4 12.131 Tf /FormType 1 /FormType 1 >> >> endobj Q 0 g stream Q q q Q /Widths [ 250 0 385 0 0 0 0 0 0 0 0 0 0 0 (+) Tj 0 g 1.007 0 0 1.007 130.989 330.484 cm /Meta316 Do << /Matrix [1 0 0 1 0 0] /Subtype /Form q 22.478 5.336 TD Q /Type /XObject /Matrix [1 0 0 1 0 0] endobj /Length 59 /XHeight 476 << q /BBox [0 0 88.214 35.886] /Resources<< /Resources<< (C\)) Tj stream /Subtype /Form /Matrix [1 0 0 1 0 0] Q Thrice of a number = 3x. /Resources<< Q >> 435 0 obj /Resources<< Q >> /BBox [0 0 88.214 16.44] << q q (38) Tj 1.005 0 0 1.007 102.382 653.441 cm q 14.966 20.154 l /BBox [0 0 88.214 16.44] /FormType 1 /FirstChar 32 /AvgWidth 445 stream q /Matrix [1 0 0 1 0 0] 121 0 obj /ProcSet[/PDF/Text] /Meta129 Do 428 0 obj stream Diabetes, also known as diabetes mellitus, is a group of common endocrine diseases characterized by sustained high blood sugar levels. q /Meta327 341 0 R